Fisika Sekolah Menengah Pertama 212°F =........K40° R =........°C122° F =........°C 323° k =........KTolong dijawab ya... ​

hermanraynorulv – April 11, 2023

212°F =........K
40° R =........°C
122° F =........°C
323° k =........K

Tolong dijawab ya...
​

212°F = 5/9 x (212 -32) + 273 K

= 5/9 x 180 + 273 K

= 100 + 273 K

= 373 K

40° R = 5/4 x 40° R

= 50°R

122° F = 5/9 x (122 - 32)°C

= 5/9 x 90 °C

= 50°C

323° k = 323 K

= 323 - 273 °C

= 59°C

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